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# Secant problems on a hp50g

Hi guys,

I am new to the hp50g. I have a uni tutorial asking me to solve the following, and I have no idea how to add the "sec" part into the equation.

It is for solving the secant length of a circular curve setout.

Photo below. any help would be much appreciated. This calculator is driving me crazy!

secant%20length.tiff

Any ideas?

This Content Originally Published by a land surveyor to Land Surveyors United Network

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### Replies to This Discussion

Paul,

Secant is the Reciprocal of Cosine:

Dave

60' equals 1 degree

12'               x?

x=0.2 degrees , so the equation becomes 600*(sec9.2/2 -1)=600*(sec4.6-1)=600*(1.0032315-1)=1.938m, where sec=1/cos4.6=1.0032315....

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