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  • Thanks For Suggestion paul

    Paul Quagge said:

    Hello sanju,

     

    arctan angle = difference in x / difference in y between two sets of coordinates...

     

    like Justin said not sure if this is what your looking for..

     

    what kind of drafting software do you have?

     

    are you doing this without software? drafting by hand?

     

    Paul

  • Thanks its work

    Kevin Barry said:

    I meant "so the bearing is headed North east".....I should always proof read twice....good job were not all perfect hey!
     
    Kevin Barry said:

    OK this is for working it out with your calculator. You didn't give a lot of detail so I imagine we need to get back to basics. Depending on your coordinate system you need to work out the differences between horizontals and the differences between the verticals. Imagine a piece of graph paper with a cross drawn on it. Zero x and Zero y are your start point. Now with your x and y differences plotted, one end of the hypotenuse will be your starting point 0,0 so your bearing will be measured from there. Now you can determine if your x and y values are positive or negative. Each quadrant of the cross on the graph paper will be for x,y values +,+ and +,- and -,- and -,+ going clockwise from the top right quadrant which is +,+. For simplicity we will imagine it is +,+ so that means x is positive and y is positive. If we call x difference as 100.000 and y difference as 173.205 we can use the arctan function on your calculator to work backwards to find the angle from the horizontal. So (opposite)173.205 divided by (adjacent)100 = 1.73205 (this is the tan of the angle you are looking for). Enter 1.73205 into your calculator and press the arctan function button (usually it is SHIFT TAN). the answer should be 60 degrees (rounded up) from 59.99998843. So the bearing is heading North west at 60degrees from horizontal. Now try it with different positive and negative combinations until you are confident and let us know what your bearing came to. If you give us your coords we can check your work to make sure you have it right. I hope this helps. Kevin.  

  • Government Professional

    I meant "so the bearing is headed North east".....I should always proof read twice....good job were not all perfect hey!
     
    Kevin Barry said:

    OK this is for working it out with your calculator. You didn't give a lot of detail so I imagine we need to get back to basics. Depending on your coordinate system you need to work out the differences between horizontals and the differences between the verticals. Imagine a piece of graph paper with a cross drawn on it. Zero x and Zero y are your start point. Now with your x and y differences plotted, one end of the hypotenuse will be your starting point 0,0 so your bearing will be measured from there. Now you can determine if your x and y values are positive or negative. Each quadrant of the cross on the graph paper will be for x,y values +,+ and +,- and -,- and -,+ going clockwise from the top right quadrant which is +,+. For simplicity we will imagine it is +,+ so that means x is positive and y is positive. If we call x difference as 100.000 and y difference as 173.205 we can use the arctan function on your calculator to work backwards to find the angle from the horizontal. So (opposite)173.205 divided by (adjacent)100 = 1.73205 (this is the tan of the angle you are looking for). Enter 1.73205 into your calculator and press the arctan function button (usually it is SHIFT TAN). the answer should be 60 degrees (rounded up) from 59.99998843. So the bearing is heading North west at 60degrees from horizontal. Now try it with different positive and negative combinations until you are confident and let us know what your bearing came to. If you give us your coords we can check your work to make sure you have it right. I hope this helps. Kevin.  

  • Government Professional

    OK this is for working it out with your calculator. You didn't give a lot of detail so I imagine we need to get back to basics. Depending on your coordinate system you need to work out the differences between horizontals and the differences between the verticals. Imagine a piece of graph paper with a cross drawn on it. Zero x and Zero y are your start point. Now with your x and y differences plotted, one end of the hypotenuse will be your starting point 0,0 so your bearing will be measured from there. Now you can determine if your x and y values are positive or negative. Each quadrant of the cross on the graph paper will be for x,y values +,+ and +,- and -,- and -,+ going clockwise from the top right quadrant which is +,+. For simplicity we will imagine it is +,+ so that means x is positive and y is positive. If we call x difference as 100.000 and y difference as 173.205 we can use the arctan function on your calculator to work backwards to find the angle from the horizontal. So (opposite)173.205 divided by (adjacent)100 = 1.73205 (this is the tan of the angle you are looking for). Enter 1.73205 into your calculator and press the arctan function button (usually it is SHIFT TAN). the answer should be 60 degrees (rounded up) from 59.99998843. So the bearing is heading North west at 60degrees from horizontal. Now try it with different positive and negative combinations until you are confident and let us know what your bearing came to. If you give us your coords we can check your work to make sure you have it right. I hope this helps. Kevin.  

  • Hello sanju,

     

    arctan angle = difference in x / difference in y between two sets of coordinates...

     

    like Justin said not sure if this is what your looking for..

     

    what kind of drafting software do you have?

     

    are you doing this without software? drafting by hand?

     

    Paul

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